//显示0 w=0x01; //行变量为第一行 for(i=0;i<8;i++){ P1=w;//行数据送P1口 P0=led0[i];delayms(1);//列数据送P0口 w<<=1;//向下移动一行 } } } void delay1ms(unsigned int ms){ unsigned

0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,

1． 程序设计内容 8X8点阵LED工作原理说明 :8X8点阵共需要64个发光二极管组成，且每个发光二极管是放置在行线和列线的交叉点上，当对应的某一列置1电平，某一行置0电平，则相应的二极管就亮；因此要实现一根柱形的亮法，

说明你的程序根本就不能控制8x8点阵LED，都不能点亮。再说了，显示一个汉字，至少要16x16的点阵，开发板上的8x8点阵只能显示一些图形，根本就不能显示汉字的。

static unsigned int tmr = 0; //1s软件定时器 static unsigned char index = 9; //图片刷新索引 TH0 = 0xFC; //重新加载初值 TL0 = 0x67;//以下代码完成LED点阵动态扫描刷新 P0 = 0xFF; //显示消隐

单片机汉字8x8点阵LED动态显示程序

一．基于51的点阵屏显示：（1）点亮第一个8*8点阵:1.首先在Proteus下选择我们需要的元件，AT89C51、74LS138、MATRIX-8*8-GREEN(在这里使用绿色的点阵)。在Proteus 6.9中8*8的点阵总共有四种颜色，分别为MATRIX-8*8-

一行一行显示呀，用取模软件获得每个字符8个字节的代码，然后1到 8行轮换扫描显示

void main(void){ unsigned char i;while (1) //如果没有while循环，将出现闪烁现象 { for(i=0;i<8;i++){ Ser_IN(a[i]);//8X8点阵列扫描 Ser_IN(b[i]);//8X8点阵行扫描 Par_OUT();//74HC595输出显示

用51单片机8×8点阵显示字母，是要用proteus仿真吧，先画出仿真图，再用取模软件画出字母X Q J，然后按行取模，每一个字母的字模是8个字节。显示时，依次取出每行的字模，按行扫描显示即可。下图是一个仿真图。

你真厉害，一位数组显示点阵实验，点阵最好是用二位数组，基本思路也就是单片机两个IO口控制点阵的行和列，定义一个二位数组控制点阵每一行要亮拿几个灯，然后下一行亮那几个灯，以此类推，快速刷出没一个亮的灯就能让

include#include#define uchar unsigned char#define uint unsigned int//---uchar code Table_of_Digits[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0

51单片机 8*8点阵26个英文字母怎么样显示 ?要从上到下的编码

用51单片机8*8点阵显示出“生日快乐”四个字，这办不到的。至少要用16X16的点阵才能显示出汉字。8*8的点阵只能显示0~9的数字。如果是仿真显示，就用4个8*8的点阵组成一个显示屏，也很简单的。要是实物开发板，那就

一行一行显示呀，用取模软件获得每个字符8个字节的代码，然后1到 8行轮换扫描显示

你真厉害，一位数组显示点阵实验，点阵最好是用二位数组，基本思路也就是单片机两个IO口控制点阵的行和列，定义一个二位数组控制点阵每一行要亮拿几个灯，然后下一行亮那几个灯，以此类推，快速刷出没一个亮的灯就能让

include#include#define uchar unsigned char#define uint unsigned int//---uchar code Table_of_Digits[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0

if(++t==250) //每个数字刷新显示一段时间 { t=0;yi++;

用51单片机8×8点阵显示字母，是要用proteus仿真吧，先画出仿真图，再用取模软件画出字母X Q J，然后按行取模，每一个字母的字模是8个字节。显示时，依次取出每行的字模，按行扫描显示即可。下图是一个仿真图。

8*8点阵是动态扫描的 静态显示也是动态扫描的结果。比如说下面这个程序：include include "74HC595.H"unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};unsigned char code b[]

用51单片机以及8*8点阵显示英文字母或者数字(最好是全部数字和字母都说说哈),静态显示就可以 谢谢啊

单片机8*8点阵（0~F十六进制数字，可做成8*8图形）仿真实例。)LED EQU P3;;;LED灯显示定义 KEY EQU P1;;;键盘接口定义 TIME EQU 30H CNTA EQU 31H CNTB EQU 32H ;---程序入口定义 ORG 0000H JMP START

对于8×8点阵的汉字而言,每一行有8个点,一个字节占用8位,共需1个字节,1×8=8个字节

这是一列列的数模。0x04对应的是左边第一列下面8个点阵的显示0x28对应的是左边第一列上八位。且上面是高位下面是低位。这样你在16x16的格子中把所有1标出来就可以组成一个欢字了

LEDTAB: DB 0C0H ;"0" 00H DB 0F9H ;"1" 01H DB 0A4H ;"2" 02H DB 0B0H ;"3" 03H DB 99H ;"4" 04H DB 92H ;"5" 05H DB 82H ;"6" 06H DB 0F8H ;"7" 07H DB 80H ;"8

8*8造汉字很困难的，你可以找一个8*8的汉字库（如果有的话），用字模提取软件（网上很多的）获取点阵字库数据，之后写入这个8*8点阵就OK了。

unsigned char code led0[]={};//字码表,你自己把你要显示的字码放进去就可以了 void main(){ unsigned char w,i;while(1){ //显示0 w=0x01; //行变量为第一行 for(i=0;i<8;i++){ P1=w;//行数

DB 0,48,8,132,132,72,48,0 DB 0,0,192,48,12,252,0,0 DB 0,252,68,68,68,132,4,0 DB 0,240,136,68,68,136,48,0 DB 16,12,4,4,132,100,28,0 DB 0,48,72,132,132,72,48,0 DB

求8*8 LED点阵的字形码

#include//单片机头文件 void delay1ms(unsigned int ms);//延时ms函数声明（可根据实际情况更改） unsigned char code led0[]={};//字码表,你自己把你要显示的字码放进去就可以了 void main() { unsigned char w,i; while(1) { //显示0 w=0x01; //行变量为第一行 for(i=0;i<8;i++) { P1=w; //行数据送P1口 P0=led0[i]; delayms(1); //列数据送P0口 w<<=1; //向下移动一行 } } } void delay1ms(unsigned int ms) { unsigned int i,j; for(i=0;i<ms;i++) for(j=0;j<110;j++) }
附件是常用的LED、液晶点阵字符取模工具。不光你那几个符号，汉字也可以取出，可以根据你的电路更改取模方式，很好用的软件。
我来帮你搞定
#include#include#define uchar unsigned char#define uint unsigned int//--------------------------------------------uchar code Table_of_Digits[40][8]={ {0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z};//---------------------------------------uchar code xdat[8]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};uchar code ydat[8]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};//---------------------------------------uchar i=0;uchar j=0;uchar t=0;uchar Num_Index,disnum;uchar key;uchar xi;uchar yi;//---------------------------------------uchar code disstr[]="C201600102020";//显示内容可以自己定义//---------------------------------------sbit we1=P1^1;sbit we2=P1^3;//---------------------------------------//主程序//---------------------------------------void main(){//P1=0x80;Num_Index=0; //从0 开始显示TMOD=0x01; //T0 方式0TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;IE=0x82;key=0;xi=0;yi=0;EX0=1;IT0=1;TR0=1; //启动T0while(1);}//---------------------------------------//外部中断0 中断函数//按键处理//---------------------------------------void ext_int0() interrupt 0{ key++; key&=0x03;}//---------------------------------------//定时器0 中断函数//显示控制//---------------------------------------void LED_Screen_Display() interrupt 1{TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;switch(key){//显示点阵图形case 0: P0=0xff; if(disstr[Num_Index]>='A')disnum=disstr[Num_Index]-'A'+10; else disnum=disstr[Num_Index]-'0'; we1=1; P0=~Table_of_Digits[disnum][i]; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=ydat[i]; we2=0; if(++i==8) i=0; //每屏一个数字由8 个字节构成 if(++t==250) //每个数字刷新显示一段时间 { t=0; if(++Num_Index==13) Num_Index=0; //显示下一个数字 } break;//流水灯“点”模式case 1: we1=1; P0=~xdat[xi]; we1=0; we2=1; P0=ydat[yi]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { t=0; yi++; if(yi>7){yi=0;xi++;} if(xi>7)xi=0; } break;//流水灯“行列”模式case 2: we1=1; P0=0x00; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=xdat[i]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { if(++i==8) i=0; //每屏一个数字由8 个字节构成 t=0; } break;default: key=0; i=0; j=0; t=0; xi=0; yi=0; Num_Index=0; we1=1; P0=0xff; we1=0; we2=1; P1=0x80; we2=0; break;}}
你真厉害，一位数组显示点阵实验，点阵最好是用二位数组，基本思路也就是单片机两个IO口控制点阵的行和列，定义一个二位数组控制点阵每一行要亮拿几个灯，然后下一行亮那几个灯，以此类推，快速刷出没一个亮的灯就能让人感觉是一个字了，好啦，给你程序你自己看吧 unsigned char code table[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; //列位 unsigned char code Dispay[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z 我建议你套用这个程序之后把延时的时间改长一点，最好到个500ms左右，这样你就可以清楚的看到点阵是怎么显示字的了
这个是有的，不仅小写，大写也有，还有其它的异形符号。 都要自己去动手做。
这个程序验证过，你可以参考试试：//-------------------------------------------//8*8矩阵循环显示字符和数字//显示字符串在数组disstr[]中申明//-------------------------------------------#include#include#define uchar unsigned char#define uint unsigned int//--------------------------------------------uchar code Table_of_Digits[40][8]={ {0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z};//---------------------------------------uchar code xdat[8]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};uchar code ydat[8]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};//---------------------------------------uchar i=0;uchar j=0;uchar t=0;uchar Num_Index,disnum;uchar key;uchar xi;uchar yi;//---------------------------------------uchar code disstr[]="C201600102020";//---------------------------------------sbit we1=P1^1;sbit we2=P1^3;//---------------------------------------//主程序//---------------------------------------void main(){//P1=0x80;Num_Index=0; //从0 开始显示TMOD=0x01; //T0 方式0TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;IE=0x82;key=0;xi=0;yi=0;EX0=1;IT0=1;TR0=1; //启动T0while(1);}//---------------------------------------//外部中断0 中断函数//按键处理//---------------------------------------void ext_int0() interrupt 0{ key++; key&=0x03;}//---------------------------------------//定时器0 中断函数//显示控制//---------------------------------------void LED_Screen_Display() interrupt 1{TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;switch(key){//显示点阵图形case 0: P0=0xff; if(Num_Index==0)disnum=disstr[Num_Index]-'A'+10; else disnum=disstr[Num_Index]-'0'; we1=1; P0=~Table_of_Digits[disnum][i]; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=ydat[i]; we2=0; if(++i==8) i=0; //每屏一个数字由8 个字节构成 if(++t==250) //每个数字刷新显示一段时间 { t=0; if(++Num_Index==13) Num_Index=0; //显示下一个数字 } break;//流水灯“点”模式case 1: we1=1; P0=~xdat[xi]; we1=0; we2=1; P0=ydat[yi]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { t=0; yi++; if(yi>7){yi=0;xi++;} if(xi>7)xi=0; } break;//流水灯“行列”模式case 2: we1=1; P0=0x00; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=xdat[i]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { if(++i==8) i=0; //每屏一个数字由8 个字节构成 t=0; } break;default: key=0; i=0; j=0; t=0; xi=0; yi=0; Num_Index=0; we1=1; P0=0xff; we1=0; we2=1; P1=0x80; we2=0; break;}}
说明你的程序根本就不能控制8x8点阵LED，都不能点亮。 再说了，显示一个汉字，至少要16x16的点阵，开发板上的8x8点阵只能显示一些图形，根本就不能显示汉字的。