一．基于51的点阵屏显示：（1）点亮第一个8*8点阵:1.首先在Proteus下选择我们需要的元件，AT89C51、74LS138、MATRIX-8*8-GREEN(在这里使用绿色的点阵)。在Proteus 6.9中8*8的点阵总共有四种颜色，分别为MATRIX-8*8-

看你程序是显示字母，旋转的方法就不行了，那样，字母是横着显示了，这不符合习惯和题目要求。修改方法是，所显示的那些字母要重新取模了，改成按列取模，程序不用改。就是CHAR_TAB表格中全部数据都重新按列取模得到。

8*8点阵是动态扫描的 静态显示也是动态扫描的结果。比如说下面这个程序：include include "74HC595.H"unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};unsigned char code b[]

一行一行显示呀，用取模软件获得每个字符8个字节的代码，然后1到 8行轮换扫描显示

unsigned char code table[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; //列位 unsigned char code Dispay[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0

include#include#define uchar unsigned char#define uint unsigned int//---uchar code Table_of_Digits[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0

51单片机 8*8点阵26个英文字母怎么样显示

e可以将“日”的右边两竖去掉来显示；f可以将“日”的最底一横，右边两竖去掉来显示；PS:你要7段显示全部数字加字母？！W怎么显示？“日”字中间你能弄出一竖？最简单的方法就是换LCD，不要以为一毛钱可以买一个满汉

26个英文字母大写是：A、B、C、D、E、F、G、H、I、J、K、L、M、N、O、P、Q、R、S、T、U、V、W、X、Y、Z。26个英文字母小写是：a、b、c、d、e、f、g、h、i、j、k、l、m、n、o、p、q、r、s、t

字母书写有规律，右倾五度正合适。大写一律上两格，头上有“辫”上两格(b，d，h，k，l)， 有“尾”下面两格拖(g，q，y)，无“辫”无“尾”中间格(a，c，e，m，n，o，r，s，u，v，w，x，z)，&#

（1）表示荧光灯种类的符号 YZ：表示普通直管型荧光灯（Y为“荧光灯”，汉语拼音的第一个字母，Z--为“直”汉语拼音的第一个字母） YK：表示快速启动型荧光灯（K为“快速启动”） YS：表示瞬时启动型荧光灯（S为“瞬

如图所示，这个是7段数码管显示字符与英文字母对照表，26个英文字母都有。望采纳。。。

Crtl + B 字体加粗。26个英文字母大写是：A、B、C、D、E、F、G、H、I、J、K、L、M、N、O、P、Q、R、S、T、U、V、W、X、Y、Z。26个英文字母大写（加粗）是：A、B、C、D、E、F、G、H、I、J、K、L

8字8位LED数码管应该就是你说的7位的，因为加上小数点就是八位了。这种数码管只能显示很少的一些字母，a，b，c，C，d，E，F，g，H，J，L，P，r，t，u，U，y。或者自己再定义几个，太抽象了也不好认。

谁知道led怎么显示英文字母w m z x k o v

你真厉害，一位数组显示点阵实验，点阵最好是用二位数组，基本思路也就是单片机两个IO口控制点阵的行和列，定义一个二位数组控制点阵每一行要亮拿几个灯，然后下一行亮那几个灯，以此类推，快速刷出没一个亮的灯就能让

include#include#define uchar unsigned char#define uint unsigned int//---uchar code Table_of_Digits[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0

if(++t==250) //每个数字刷新显示一段时间 { t=0;yi++;

用51单片机8×8点阵显示字母，是要用proteus仿真吧，先画出仿真图，再用取模软件画出字母X Q J，然后按行取模，每一个字母的字模是8个字节。显示时，依次取出每行的字模，按行扫描显示即可。下图是一个仿真图。

8*8点阵是动态扫描的 静态显示也是动态扫描的结果。比如说下面这个程序：include include "74HC595.H"unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};unsigned char code b[]

用51单片机以及8*8点阵显示英文字母或者数字(最好是全部数字和字母都说说哈),静态显示就可以 谢谢啊

一．基于51的点阵屏显示：（1）点亮第一个8*8点阵:1.首先在Proteus下选择我们需要的元件，AT89C51、74LS138、MATRIX-8*8-GREEN(在这里使用绿色的点阵)。在Proteus 6.9中8*8的点阵总共有四种颜色，分别为MATRIX-8*8-

一行一行显示呀，用取模软件获得每个字符8个字节的代码，然后1到 8行轮换扫描显示

uchar i=0,j=0,t=0,Num_Index,key,xi,yi;sbit we1=P1^1;sbit we2=P1^3;//主程序 void main(){ //P1=0x80;Num_Index=0; //从0 开始显示 TMOD=0x01; //T0 方式0 TH0=(65536-2000)/256; //2ms

include#include#define uchar unsigned char#define uint unsigned int//---uchar code Table_of_Digits[40][8]={{0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0

8*8点阵是动态扫描的 静态显示也是动态扫描的结果。比如说下面这个程序：include include "74HC595.H"unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};unsigned char code b[]

你真厉害，一位数组显示点阵实验，点阵最好是用二位数组，基本思路也就是单片机两个IO口控制点阵的行和列，定义一个二位数组控制点阵每一行要亮拿几个灯，然后下一行亮那几个灯，以此类推，快速刷出没一个亮的灯就能让

用51单片机8×8点阵显示字母，是要用proteus仿真吧，先画出仿真图，再用取模软件画出字母X Q J，然后按行取模，每一个字母的字模是8个字节。显示时，依次取出每行的字模，按行扫描显示即可。下图是一个仿真图。

谁会51单片机8×8点阵显示X Q J字母?

#include#include#define uchar unsigned char#define uint unsigned int//--------------------------------------------uchar code Table_of_Digits[40][8]={ {0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z};//---------------------------------------uchar code xdat[8]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};uchar code ydat[8]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};//---------------------------------------uchar i=0;uchar j=0;uchar t=0;uchar Num_Index,disnum;uchar key;uchar xi;uchar yi;//---------------------------------------uchar code disstr[]="C201600102020";//显示内容可以自己定义//---------------------------------------sbit we1=P1^1;sbit we2=P1^3;//---------------------------------------//主程序//---------------------------------------void main(){//P1=0x80;Num_Index=0; //从0 开始显示TMOD=0x01; //T0 方式0TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;IE=0x82;key=0;xi=0;yi=0;EX0=1;IT0=1;TR0=1; //启动T0while(1);}//---------------------------------------//外部中断0 中断函数//按键处理//---------------------------------------void ext_int0() interrupt 0{ key++; key&=0x03;}//---------------------------------------//定时器0 中断函数//显示控制//---------------------------------------void LED_Screen_Display() interrupt 1{TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;switch(key){//显示点阵图形case 0: P0=0xff; if(disstr[Num_Index]>='A')disnum=disstr[Num_Index]-'A'+10; else disnum=disstr[Num_Index]-'0'; we1=1; P0=~Table_of_Digits[disnum][i]; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=ydat[i]; we2=0; if(++i==8) i=0; //每屏一个数字由8 个字节构成 if(++t==250) //每个数字刷新显示一段时间 { t=0; if(++Num_Index==13) Num_Index=0; //显示下一个数字 } break;//流水灯“点”模式case 1: we1=1; P0=~xdat[xi]; we1=0; we2=1; P0=ydat[yi]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { t=0; yi++; if(yi>7){yi=0;xi++;} if(xi>7)xi=0; } break;//流水灯“行列”模式case 2: we1=1; P0=0x00; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=xdat[i]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { if(++i==8) i=0; //每屏一个数字由8 个字节构成 t=0; } break;default: key=0; i=0; j=0; t=0; xi=0; yi=0; Num_Index=0; we1=1; P0=0xff; we1=0; we2=1; P1=0x80; we2=0; break;}}
8*8点阵是动态扫描的 静态显示也是动态扫描的结果。 比如说下面这个程序： #include #include "74HC595.H" unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; unsigned char code b[]={0x00,0x7F,0x40,0x40,0x40,0x00,0x00,0x00};/*"L",0*/ void main(void) { unsigned char i; while (1) //如果没有while循环，将出现闪烁现象 { for(i=0;i<8;i++) { Ser_IN(a[i]);//8X8点阵列扫描 Ser_IN(b[i]);//8X8点阵行扫描 Par_OUT();//74HC595输出显示 } i=0; } } 程序里面还要包含"74HC595.H" 把它放在工程文件夹里面就可以了。"74HC595.H"具体程序如下： #ifndef __74HC595_H__ #define __74HC595_H__ sbit SD = P1^4; //串行数据输入 sbit ST_CK = P1^5; //存储寄存器时钟输入 sbit SH_CK = P1^6; //移位寄存器时钟输入 void Ser_IN(unsigned char Data); //串行数据输入 void Par_OUT(void); //串行数据输出 //void Ser_Par(unsigned char Data); //串行输入,并行输出 //串行数据输入 void Ser_IN(unsigned char Data) { unsigned char i; for(i = 0; i < 8; i++) { SH_CK = 0; //CLOCK_MAX=100MHz SD = Data & 0x80; Data <<= 1; SH_CK = 1; } } //并行数据输出 void Par_OUT(void) { ST_CK = 0; ST_CK = 1; } //串行输入,并行输出 void Ser_Par(unsigned char Data) { Ser_IN(Data); Par_OUT(); } 当然，由于不同的单片机引脚不同，可能编译没错，但是实际是显示不了的。 就是那么多，望采纳。
我来帮你搞定
#include#include#define uchar unsigned char#define uint unsigned int//--------------------------------------------uchar code Table_of_Digits[40][8]={ {0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z};//---------------------------------------uchar code xdat[8]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};uchar code ydat[8]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};//---------------------------------------uchar i=0;uchar j=0;uchar t=0;uchar Num_Index,disnum;uchar key;uchar xi;uchar yi;//---------------------------------------uchar code disstr[]="C201600102020";//显示内容可以自己定义//---------------------------------------sbit we1=P1^1;sbit we2=P1^3;//---------------------------------------//主程序//---------------------------------------void main(){//P1=0x80;Num_Index=0; //从0 开始显示TMOD=0x01; //T0 方式0TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;IE=0x82;key=0;xi=0;yi=0;EX0=1;IT0=1;TR0=1; //启动T0while(1);}//---------------------------------------//外部中断0 中断函数//按键处理//---------------------------------------void ext_int0() interrupt 0{ key++; key&=0x03;}//---------------------------------------//定时器0 中断函数//显示控制//---------------------------------------void LED_Screen_Display() interrupt 1{TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;switch(key){//显示点阵图形case 0: P0=0xff; if(disstr[Num_Index]>='A')disnum=disstr[Num_Index]-'A'+10; else disnum=disstr[Num_Index]-'0'; we1=1; P0=~Table_of_Digits[disnum][i]; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=ydat[i]; we2=0; if(++i==8) i=0; //每屏一个数字由8 个字节构成 if(++t==250) //每个数字刷新显示一段时间 { t=0; if(++Num_Index==13) Num_Index=0; //显示下一个数字 } break;//流水灯“点”模式case 1: we1=1; P0=~xdat[xi]; we1=0; we2=1; P0=ydat[yi]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { t=0; yi++; if(yi>7){yi=0;xi++;} if(xi>7)xi=0; } break;//流水灯“行列”模式case 2: we1=1; P0=0x00; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=xdat[i]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { if(++i==8) i=0; //每屏一个数字由8 个字节构成 t=0; } break;default: key=0; i=0; j=0; t=0; xi=0; yi=0; Num_Index=0; we1=1; P0=0xff; we1=0; we2=1; P1=0x80; we2=0; break;}}
8字8位LED数码管应该就是你说的7位的，因为加上小数点就是八位了。这种数码管只能显示很少的一些字母，a，b，c，C，d，E，F，g，H，J，L，P，r，t，u，U，y。或者自己再定义几个，太抽象了也不好认。
康佳LED50M5580AF不开机，指示灯不亮是正常情况。电视机本就应该不开机，指示灯不会亮。因为没有给电视机通电，电视内部电源没有工作，自然指示灯不会亮。如果是已经给电视机通电（220V开关已经接通），即电视机处于待机状态，指示灯不亮，按遥控开机电视机可以正常工作，这时指示灯亮，说明这个双色指示灯待机指示灯损坏，或线路板以及引线断了。如果是已经给电视机通电（220V开关已经接通），电视机应该处于待机状态，指示灯不亮，按遥控开机电视机也不工作，说明电视机已经损坏。可以打开外壳，先直观检查是否有元器件明显损坏，比如电阻器烧焦、烧断，电解电容器鼓包、流液，集成电路、晶体管出现裂纹等等。没有明显损坏，就检查保险管，看看它是烧断还是炸裂、炸断的，如果是烧断，可以先换一个试试，因为它损坏，可能是电源波动较大或者输出不小心短路造成的。如果是炸裂、炸断的，就不能直接换保险管就开机试，这种情况大多数是整流管或者输出功率管击穿短路造成的。
#include#include#define uchar unsigned char#define uint unsigned int//--------------------------------------------uchar code Table_of_Digits[40][8]={ {0x1C,0x22,0x22,0x22,0x22,0x22,0x22,0x1C},//0 {0x08,0x18,0x08,0x08,0x08,0x08,0x08,0x1C},//1 {0x1C,0x22,0x02,0x02,0x1C,0x20,0x20,0x3E},//2 {0x1C,0x22,0x02,0x1C,0x02,0x02,0x22,0x1C},//3 {0x08,0x18,0x28,0x48,0x7C,0x08,0x08,0x08},//4 {0x3E,0x20,0x20,0x3E,0x02,0x02,0x22,0x1C},//5 {0x1C,0x22,0x20,0x3C,0x22,0x22,0x22,0x1C},//6 {0x3E,0x02,0x04,0x08,0x10,0x10,0x10,0x10},//7 {0x1C,0x22,0x22,0x1C,0x22,0x22,0x22,0x1C},//8 {0x1C,0x22,0x22,0x22,0x1E,0x02,0x22,0x1C},//9 {0x00,0x1C,0x22,0x22,0x22,0x3E,0x22,0x22},//A {0x00,0x3C,0x22,0x22,0x3E,0x22,0x22,0x3C},//B {0x00,0x1C,0x22,0x20,0x20,0x20,0x22,0x1C},//C {0x00,0x3C,0x22,0x22,0x22,0x22,0x22,0x3C},//D {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x3E},//E {0x00,0x3E,0x20,0x20,0x3E,0x20,0x20,0x20},//F {0x00,0x1C,0x22,0x20,0x3E,0x22,0x22,0x1C},//G {0x00,0x22,0x22,0x22,0x3E,0x22,0x22,0x22},//H {0x00,0x1C,0x08,0x08,0x08,0x08,0x08,0x1C},//I {0x00,0x3E,0x08,0x08,0x08,0x08,0x28,0x18},//J {0x00,0x20,0x2C,0x30,0x20,0x30,0x2C,0x20},//K {0x00,0x20,0x20,0x20,0x20,0x20,0x20,0x3E},//L {0x00,0x42,0x66,0x5A,0x42,0x42,0x42,0x42},//M {0x00,0x00,0x2C,0x32,0x22,0x22,0x22,0x22},//n {0x00,0x1C,0x22,0x22,0x22,0x22,0x22,0x1C},//O {0x00,0x3C,0x22,0x22,0x3C,0x20,0x20,0x20},//P {0x00,0x1C,0x22,0x22,0x22,0x2A,0x26,0x1F},//Q {0x00,0x38,0x24,0x24,0x38,0x30,0x28,0x24},//R {0x00,0x1C,0x22,0x20,0x1C,0x02,0x22,0x1C},//S {0x00,0x3E,0x08,0x08,0x08,0x08,0x08,0x08},//T {0x00,0x42,0x42,0x42,0x42,0x42,0x42,0x3C},//U {0x00,0x22,0x22,0x22,0x14,0x14,0x08,0x00},//V {0x00,0x41,0x41,0x49,0x55,0x55,0x63,0x41},//W {0x00,0x00,0x42,0x24,0x18,0x18,0x24,0x42},//X {0x00,0x22,0x22,0x14,0x08,0x10,0x20,0x00},//Y {0x00,0x3E,0x02,0x04,0x08,0x10,0x20,0x3E},//Z};//---------------------------------------uchar code xdat[8]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};uchar code ydat[8]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};//---------------------------------------uchar i=0;uchar j=0;uchar t=0;uchar Num_Index,disnum;uchar key;uchar xi;uchar yi;//---------------------------------------uchar code disstr[]="C201600102020";//显示内容可以自己定义//---------------------------------------sbit we1=P1^1;sbit we2=P1^3;//---------------------------------------//主程序//---------------------------------------void main(){//P1=0x80;Num_Index=0; //从0 开始显示TMOD=0x01; //T0 方式0TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;IE=0x82;key=0;xi=0;yi=0;EX0=1;IT0=1;TR0=1; //启动T0while(1);}//---------------------------------------//外部中断0 中断函数//按键处理//---------------------------------------void ext_int0() interrupt 0{ key++; key&=0x03;}//---------------------------------------//定时器0 中断函数//显示控制//---------------------------------------void LED_Screen_Display() interrupt 1{TH0=(65536-2000)/256; //2ms 定时TL0=(65536-2000)%256;switch(key){//显示点阵图形case 0: P0=0xff; if(disstr[Num_Index]>='A')disnum=disstr[Num_Index]-'A'+10; else disnum=disstr[Num_Index]-'0'; we1=1; P0=~Table_of_Digits[disnum][i]; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=ydat[i]; we2=0; if(++i==8) i=0; //每屏一个数字由8 个字节构成 if(++t==250) //每个数字刷新显示一段时间 { t=0; if(++Num_Index==13) Num_Index=0; //显示下一个数字 } break;//流水灯“点”模式case 1: we1=1; P0=~xdat[xi]; we1=0; we2=1; P0=ydat[yi]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { t=0; yi++; if(yi>7){yi=0;xi++;} if(xi>7)xi=0; } break;//流水灯“行列”模式case 2: we1=1; P0=0x00; we1=0; P0=0xff; //输出位码和段码 we2=1; P0=xdat[i]; we2=0; if(++t==250) //每个数字刷新显示一段时间 { if(++i==8) i=0; //每屏一个数字由8 个字节构成 t=0; } break;default: key=0; i=0; j=0; t=0; xi=0; yi=0; Num_Index=0; we1=1; P0=0xff; we1=0; we2=1; P1=0x80; we2=0; break;}}
8*8点阵是动态扫描的 静态显示也是动态扫描的结果。 比如说下面这个程序： #include #include "74HC595.H" unsigned char code a[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; unsigned char code b[]={0x00,0x7F,0x40,0x40,0x40,0x00,0x00,0x00};/*"L",0*/ void main(void) { unsigned char i; while (1) //如果没有while循环，将出现闪烁现象 { for(i=0;i<8;i++) { Ser_IN(a[i]);//8X8点阵列扫描 Ser_IN(b[i]);//8X8点阵行扫描 Par_OUT();//74HC595输出显示 } i=0; } } 程序里面还要包含"74HC595.H" 把它放在工程文件夹里面就可以了。"74HC595.H"具体程序如下： #ifndef __74HC595_H__ #define __74HC595_H__ sbit SD = P1^4; //串行数据输入 sbit ST_CK = P1^5; //存储寄存器时钟输入 sbit SH_CK = P1^6; //移位寄存器时钟输入 void Ser_IN(unsigned char Data); //串行数据输入 void Par_OUT(void); //串行数据输出 //void Ser_Par(unsigned char Data); //串行输入,并行输出 //串行数据输入 void Ser_IN(unsigned char Data) { unsigned char i; for(i = 0; i < 8; i++) { SH_CK = 0; //CLOCK_MAX=100MHz SD = Data & 0x80; Data <<= 1; SH_CK = 1; } } //并行数据输出 void Par_OUT(void) { ST_CK = 0; ST_CK = 1; } //串行输入,并行输出 void Ser_Par(unsigned char Data) { Ser_IN(Data); Par_OUT(); } 当然，由于不同的单片机引脚不同，可能编译没错，但是实际是显示不了的。 就是那么多，望采纳。